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发表于 1-12-2012 21:55:02|来自:新加坡
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cjj 发表于 1-12-2012 16:44
GIVEN the equation of a line is -8x+4y=15,find
(a) the gradient of the line
(b) t ...
Solution:
(a) When x=0, we get y=15/4.
When y=0, we get x=-15/8.
Points (0, 15/4) and (-15/8, 0) are on this line.
Gradient of the line = (y2-y1)/(x2-x1)=(15/4)/(15/8)=2.
(b) y-intercept is 15/4.
(If you write the line in form y=mx+b, then b is the y-intercept or (0, b) is the y-intercept. I'm not sure about this point, depending on the concept of the y-intercept your textbook stated.)
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